TeX Quellcode:
\begin{array}{crclcl}& \mathbb{D} &=& \mathbb{R}\setminus_{\{1\}} \\ \\& \dfrac{2x^3-5x^2+4x}{(x-1)^2} &=& 0 &\vert& \cdot (x-1)^2 \cr & 2x^3-5x^2+4x &=& 0 \cr & x\left(2x^2-5x+4\right) &=& 0 &\vert& \text{Satz vom Nullprodukt} \cr \text{Faktor 1:} & x_{1} &=& 0 \in\mathbb{D} \cr\cr \text{Faktor 2:} & 2x^2-5x+4 &=& 0 &\vert& \text{a-b-c-Formel} \cr & x_{2,3} &=& \dfrac{5\pm\sqrt{25-32}}{4} \cr& x_{2,3} &=& \dfrac{5\pm\sqrt{-7}}{4} \end{array}