TeX Quellcode:

\begin{array}{lclcrcl}\quad\mathbb{D}&=&\mathbb{R}\setminus_{\left\{\frac{7}{12}\right\}} \cr \cr f(q) &=& \dfrac{\left(- 12 q+7\right)^{4}}{144 q^{2} - 168 q + 49}\cr \cr &=& \dfrac{\left(- 12 q+7\right)^{4}}{\left(- 12 q+7\right)^{2}} \cr \cr &=& \left( - 12 q+7\right)^{2}\cr \cr &=& 144q^2-168q + 49\cr \cr \cr f'(q) &=& 288 q - 168\end{array}