TeX Quellcode:
\begin{array}{rcl} \dfrac{8}{z} + \left(\dfrac{z} {2}-12\right) \left(1+\dfrac{4}{z}\right) &=& \dfrac{8}{z} + \dfrac{z}{2} \cdot 1 + \dfrac{z}{2} \cdot \dfrac{4}{z} - 12 \cdot 1 -12 \cdot \dfrac{4}{z} \cr \cr &=& \dfrac{8}{z} + \dfrac{z}{2} + 2 - 12 - \dfrac{48}{z} \cr \cr &=& \dfrac{z}{2} - 10 - \dfrac{40}{z} \end{array}