TeX Quellcode:

\begin{array}{rcl} \displaystyle\int \limits_1^2 \left( x+\dfrac{1}{x^2} \right) dt &=& \left( x+\dfrac{1}{x^2} \right) \int \limits_1^2 1 \, dt \cr\cr &=& \left( x+\dfrac{1}{x^2} \right) \cdot \left[ t \right]_1^2 \cr\cr &=& \left( x+\dfrac{1}{x^2} \right) \cdot \left( 2-1 \right) \cr\cr &=&\left(x+\dfrac{1}{x^2} \right) \cdot 1 \cr\cr &=& x+\dfrac{1}{x^2} \end{array}