TeX Quellcode:

\begin{array}{rcl} \displaystyle\int \limits_4^6 \dfrac{x-3}{x^2-6x+9} \, dx &=& \displaystyle\int \limits_4^6 \dfrac{x-3}{(x-3)^2} \, dx \cr\cr&=& \displaystyle\int \limits_4^6 \dfrac{1}{x-3} \, dx \cr\cr&=& \left[ \ln\left(\left|x-3\right|\right) \right]_4^6 \cr\cr&=& \ln\left(\left|6-3\right|\right) - \ln\left(\left|4-3\right|\right) \cr\cr&\approx& 1{,}10 \end{array}