TeX Quellcode:

\begin{array}{rcl} \sqrt{\left(\dfrac{3}{4}\right)^2+1+3\sqrt{\dfrac{3}{4}-\dfrac{1}{2}}} &=& \dfrac{3}{4}+1 \\\\\sqrt{\dfrac{9}{16}+1+3\sqrt{\dfrac{1}{4}}} &=& \dfrac{7}{4} \\\\\sqrt{\dfrac{9}{16}+1+\dfrac{3}{2}} &=& \dfrac{7}{4} \\\\\sqrt{\dfrac{49}{16}} &=& \dfrac{7}{4} \\\\\dfrac{7}{4} &=& \dfrac{7}{4}\end{array}