TeX Quellcode:
\begin{array}{rcl}\displaystyle\int \limits_{-2}^2 \left(-\dfrac{1}{4}x+t\right) \, dx &=& \left[-\dfrac{1}{8}x^2+t x\right]_{-2}^2 \cr \cr &=& -\dfrac{1}{8}\cdot 4+2t - \left(-\dfrac{1}{8}\cdot 4-2t \right) \cr \cr &=& 4t \end{array}