TeX Quellcode:

\begin{array}{rcl}z_0 &=& \sqrt[3]{64}\cdot\left(\cos\left(\dfrac{\pi+2\cdot 0\cdot\pi}{3}\right)+i\cdot\sin\left(\dfrac{\pi+2\cdot 0\cdot\pi}{3}\right)\right) \\&=& 4\left(\cos\left(\dfrac{\pi}{3}\right)+i\cdot\sin\left(\dfrac{\pi}{3}\right)\right) \\&=& 4\left(\dfrac{1}{2}+i\dfrac{\sqrt{3}}{2}\right) \\&=& 2+2\sqrt{3}i \\\\z_1 &=& \sqrt[3]{64}\cdot\left(\cos\left(\dfrac{\pi+2\cdot 1\cdot\pi}{3}\right)+i\cdot\sin\left(\dfrac{\pi+2\cdot 1\cdot\pi}{3}\right)\right) \\&=& 4\left(\cos\left(\pi\right)+i\cdot\sin\left(\pi\right)\right) \\&=& 4\left(-1+i\cdot 0\right) \\&=& -4 \\\\z_2 &=& \sqrt[3]{64}\cdot\left(\cos\left(\dfrac{\pi+2\cdot 2\cdot\pi}{3}\right)+i\cdot\sin\left(\dfrac{\pi+2\cdot 2\cdot\pi}{3}\right)\right) \\&=& 4\left(\cos\left(\dfrac{5\pi}{3}\right)+i\cdot\sin\left(\dfrac{5\pi}{3}\right)\right) \\&=& 4\left(\dfrac{1}{2}-i\dfrac{\sqrt{3}}{2}\right) \\&=& 2-2\sqrt{3}i \\\\\mathbb{L} &=& \{2+2\sqrt{3}i \; ; \; -4 \; ; \; 2-2\sqrt{3}i\}\end{array}