TeX Quellcode:

\begin{array}{rclcl} (8+3x)^2 &=& -2(19-12x-5x^2)-10 \cr 64+48x+9x^2 &=& -2(19-12x-5x^2)-10 \cr 64+48x+9x^2 &=& -38+24x+10x^2-10 & \vert & -10x^2 -24x+48 \cr -x^2+24x+112 &=& 0 & \vert & \cdot (-1) \cr x^2-24x-112 &=& 0 \cr x_{1,2} &=& 12 \pm \sqrt{144+112} \cr\cr x_1 &=& 12+16 = 28 \cr x_2 &=& 12-16 = -4 \cr\cr \mathbb{L} &=& \{-4; 28\} \end{array}