TeX Quellcode:

\begin{array}{rclcl} \sqrt{4x+8}+\sqrt{12x-24} &=& 0 &\vert& -\sqrt{12x-24} \\ \sqrt{4x+8} &=& -\sqrt{12x-24} &\vert& ()^2 \\ 4x+8 &=& 12x-24 &\vert& -8 -12x \\-8x &=& -32 &\vert& :(-8) \\ x &=& 4 \in \mathbb{D} \\\end{array}