TeX Quellcode:

\begin{array}{rclcl} 0 &=& 9z^2+3z-2 &\vert& :9 \cr\cr 0 &=& z^2+\dfrac13 z-\dfrac29 &\vert& \text{p-q-Formel} \cr\cr z_{1,2}&=& -\dfrac16 \pm \sqrt{\left(\dfrac16\right)^2 + \dfrac29}\cr\cr z_{1,2} &=& -\dfrac16 \pm\sqrt{\dfrac{9}{36}} \cr\cr z_1 &=& -\dfrac16+\dfrac36 = \dfrac13 \cr z_2 &=& -\dfrac16-\dfrac36 = -\dfrac23\end{array}