TeX source:
\begin{array}{rclcl}0 &=& \dfrac{\sqrt{64}}{\sqrt{8x}}-128 &\vert& +128 \\\\128 &=& \dfrac{8}{\sqrt{8x}} &\vert& : 8 \\\\16 &=& \dfrac{1}{\sqrt{8x}} &\vert& \text{Kehrwert} \\\\\dfrac{1}{16} &=& \sqrt{8x} &\vert& ()^2 \\\\\dfrac{1}{256} &=& 8x &\vert& :8 \\\\\dfrac{1}{2.048} &=& x \in \mathbb{D}\end{array}