TeX Quellcode:

\begin{array}{rclll} \dfrac{du}{dx} &=& -12 \cr dx &=& -\dfrac{du}{12} \cr\cr\cr \displaystyle\int \limits_{-2}^1 e^{-12x+5} \,dx &=& \displaystyle\int \limits_{-2}^1 -e^{u}\,\dfrac{du}{12} \cr\cr &=& -\dfrac{1}{12}\displaystyle\int \limits_{-2}^1 e^{u}\, du \cr &=& -\dfrac{1}{12} \left[e^{u} \right]_{-2}^1 \end{array}