TeX Quellcode:

\begin{array}{rclll} \mathbb{D} &=& \mathbb{R}\setminus_{\left\{-2\right\}} \cr\cr \dfrac{t^2+16t-4}{t+2}-10 &=& t &\vert & \cdot(t+2) \cr t^2+16t-4-10(t+2) &=& t(t+2) \cr t^2+16t-4-10t-20 &=& t^2+2t \cr t^2+6t-24 &=& t^2+2t &\vert & -t^2-2t+24 \cr 4t &=& 24 &\vert & :4 \cr t &=& 6 \;\in\;\mathbb{D} \cr\cr \mathbb{L} &=& \left\{6\right\} \end{array}