TeX Quellcode:

\begin{array}{rclll} \mathbb{D} &=& \mathbb{R}\setminus_{\left\{1\right\}} \cr\cr f'(t) &=& \dfrac{\left(4t^3-9t^2+5\right)(t-1)-\left(t^4-3t^3+5t-5\right)\cdot 1}{(t-1)^2} \cr\cr &=& \dfrac{3t^4-10t^3+9t^2}{(t-1)^2} \cr\cr\cr f''(t) &=& \dfrac{\left(12t^3-30t^2+18t\right)(t-1)^2-\left(3t^4-10t^3+9t^2\right)\cdot 2(t-1)}{(t-1)^4} \cr\cr &=& \dfrac{\left(12t^3-30t^2+18t\right)(t-1)-\left(3t^4-10t^3+9t^2\right)\cdot 2}{(t-1)^3} \cr\cr &=& \dfrac{6t^4-22t^3+30t^2-18t}{(t-1)^3} \end{array}