TeX Quellcode:

\begin{array}{rclll} f''(x) &=& \dfrac{-70}{(-6x^2+16x+1)^{\frac{3}{2}}} \cr\cr f''\left(\dfrac{4}{3}\right) &=& \dfrac{-70}{\left(-6 \cdot \left(\dfrac{4}{3}\right)^2+16 \cdot \dfrac{4}{3}+1\right)^{\frac{3}{2}}} \quad \approx \quad -1{,}76 \quad < \quad 0 & & \Rightarrow \text{Hochpunkt}\end{array}