TeX Quellcode:

\begin{array}{rclll} f\left(12\right) &=& \dfrac{2}{3} \log_2 \left(\dfrac{2}{12}\right)+1 &=&\dfrac{3+2\log_{2}\left(\frac{1}{6}\right)}{3} \quad \rightarrow \quad P_1\left( 12 \mid \dfrac{3+2\log_{2}\left(\frac{1}{6}\right)}{3}\right)\end{array}