TeX Quellcode:

\begin{array}{rclll}\dfrac{x^2-8}{3(x-4)} &=& \dfrac{x^3-4x(-0{,}25x+2)-8}{3x^2-9x-12} \cr\cr \dfrac{x^2-8}{3(x-4)} &=& \dfrac{x^3+x^2-8x-8}{3(x^2-3x-4)} &\vert & \cdot 3 \cr\cr \dfrac{x^2-8}{x-4} &=& \dfrac{x^3+x^2-8x-8}{x^2-3x-4} \cr\cr \dfrac{\left(x^2-8\right)\left(x^2-3x-4\right)}{(x-4)\left(x^2-3x-4\right)} &=& \dfrac{\left(x^3+x^2-8x-8\right)(x-4)}{\left(x^2-3x-4\right)(x-4)} &\vert & \cdot\left(x^2-3x-4\right)(x-4)\cr\cr x^4-3x^3-12x^2+24x+32 &=& x^4-3x^3-12x^2+24x+32 &\vert & -x^4+3x^3+12x^2-24x-32 \cr\cr 0 &=& 0\cr\cr \mathbb{L} &=& \mathbb{R}\setminus_{\left\{-1;\;4\right\}} \end{array}